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CocosCreator 2.4.5 整合Line登入(IOS App)

  • 作家相片: 承鑫 郭
    承鑫 郭
  • 2021年7月22日
  • 讀畢需時 1 分鐘


建立Line Provider以及Line Login Channel



CocosCreator建立Login按鈕以及綁定事件

//Line登入
 lineLogin: function () {
 console.log("Line login");

 if (cc.sys.isNative) { . 
     if (cc.sys.os == cc.sys.OS_ANDROID) {
     } else if (cc.sys.os == cc.sys.OS_IOS) {
         let className = "AppController";
         let methodName = "lineLogin";
         jsb.reflection.callStaticMethod(className, methodName);
     }
 }
  

Xcode專案設定(CocosCreator導出的專案為ObjectiveC)

LineSDK.framework

CoreTelephony.framework

Security.framework

  • Build Phases => Copy Bundle Resources 加入以下bundle

LineSDKResource.bundle

  • 使用 Open As => Source Code 編輯 Info.plist


LineSDKConfig</key>
 <dict>
 <key>ChannelID</key>
 <string>123456789</string>
 </dict>
 <key>CFBundleURLTypes</key>
 <array>
 <dict>
 <key>CFBundleTypeRole</key>
 <string>Editor</string>
 <key>CFBundleURLSchemes</key>
 <array>
 <string>line3rdp.$(PRODUCT_BUNDLE_IDENTIFIER)</string>
 </array>
 </dict>
 </array>
 <key>LSApplicationQueriesSchemes</key>
 <array>
 <string>lineauth2</string>
 <string>line3rdp.$(PRODUCT_BUNDLE_IDENTIFIER)</string>
 </array>

  • AppController.mm 加入以下程式碼

1.設置line代理

 // Set the LINE Login Delegate
 [LineSDKLogin sharedInstance].delegate = self;

2.設定開啟第三方line App

- (BOOL)application:(UIApplication *)app openURL:(NSURL *)url options:(NSDictionary *)options
{
 return [[LineSDKLogin sharedInstance] handleOpenURL:url];
}

3.Login成功Callback設定

#pragma mark LineSDKLoginDelegate


- (void)didLogin:(LineSDKLogin *)login
 credential:(LineSDKCredential *)credential
 profile:(LineSDKProfile *)profile
 error:(NSError *)error
{
 if (error) {
 NSLog(@"LINE Login Failed with Error: %@", error.description);
 return;
 }
 
 NSLog(@"LINE Login Succeeded");
 //做Login成功要做的事
}

連結你的Line Channel和App


Demo



疑難排解

  • Assigning to 'id<LineSDKLoginDelegate> _Nullable' from incompatible type 'AppController *'

Sol:@interface AppController () 後面加 <LineSDKLoginDelegate>


 
 
 

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